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1. x^2+y^2-6-k=0 has radius 4. Find centre of the circle and value of k
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2. (Original post by daryl.c)
x^2+y^2-6-k=0 has radius 4. Find centre of the circle and value of k
What have you tried?
3. its given me k=-16 and c (0,3) but my friend got something else
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4. (Original post by daryl.c)
its given me k=-16 and c (0,3) but my friend got something else
This is incorrect, however, did you post the correct equation in your original post? Did you mean to say ?
5. yeah its just dont have -6y its just -6
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6. (Original post by daryl.c)
yeah its just dont have -6y its just -6
So then your centre is off. Clearly is must be (0,0).

Then the equation can be rearranged to say and comparison to the general equation of the circle should be able to give you the appropriate equation concerning the radius and .
7. thx mate you got the same as my friend so it must be right c (0,0) with k=10?
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8. (Original post by daryl.c)
thx mate you got the same as my friend so it must be right c (0,0) with k=10?
That's right.

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