e/z notation isomerism help! Watch

Death_Chronic
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#1
Report Thread starter 11 years ago
#1
ok, the skeletal diagram of my molecule is:


i'm stuck on where would the E/Z isomerism can be located at since there is a diphenol ring?

many thanks for all your help guys!:tsr2:
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vVPiKaVv
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#2
Report 11 years ago
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The E/Z isomerism is located at the N=C bond. There can't be E/Z isomerism due to the double bonds in a ring because you can't rotate it such that the two substituents on either side of the double bond will be in a different position relative to the 2 substituents on the other side of the double bond. Not sure if you get what I meant, but remember the criteria for E/Z or cis-trans isomerism and link the part about restricted rotation to this.

In this case, the lone pair on the N atom is considered to be a 'substituent', just in case you didn't know about it..
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Death_Chronic
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#3
Report Thread starter 11 years ago
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thank you ^^
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