Help with maths question

username3638758

It’s all about sketching reciprocals and I got stuck on riding the x intercept > :frown:

.

y=(6) - 3/(5x-1)^2

I tried to but got like very dodgy , weird fractions with square roots and that

Reply 1

ManLike007

Original post by AestheticMedic

I got stuck on riding the x intercept > :frown:

I can't tell whether you're stuck on sketching or calculating the x coordinate. To calculate the x coordinate you know this occurs at y=0.

If you would like to sketch it and see the transformation step by step, you can say

Let

f(x) = \frac{1}{x^{2}}

Hence,

\frac{1}{(5x)^{2}} = f(5x)

I think you get the jist, keep doing the transformations until you're left with

y=6-\frac{3}{(5x-1)^{2}}

in terms of f(x) and this'll tell you the transformation of the graph.

(edited 6 years ago)

Reply 2

RDKGames

Study Forum Helper

Original post by AestheticMedic

It’s all about sketching reciprocals and I got stuck on riding the x intercept > :frown:

.

y=(6) - 3/(5x-1)^2

I tried to but got like very dodgy , weird fractions with square roots and that

For x-intercepts you say

y=0

so just...

0=6-\dfrac{3}{(5x-1)^2}

\Rightarrow 0=6(5x-1)^2-3

and this just seems like a quadratic to solve, and yes there will be a

\sqrt{2}

in there, so the roots aren't rational, but you can convert them both to decimal form for the first few digits to see whereabouts on the x-axis they lie.