Hah sure, sorry about that.
Well when I use the variance as 0.072 i get:
(11.930-11.9)/√(0.072/36) = 0.6708
And 1% range being 2.326, shows that it isn't. However book says 2.5, which leads me to believe that 0.072 is not the variance, but the standard deviation.
As from our equation above:
(11.930-11.9)/(0.072/√36) = 2.5
What do you reckon?