Ionic equilibrium

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Saj079
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#1
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#1
In a liter of a 0.1 M solution, acetic acid was found by conductivity analysis to dissociate into 1.32 x 10 –3 gram ions (moles) each of hydrogen ion and acetate ion at 25C. What is the acidity constant, Ka for acetic acid?
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ambershell27
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#2
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You've stated units grams, then put moles in brackets? So is it mass or moles? Either way, you can calculate moles from mass and then concentration from moles (vol=1litre=1dm^3). Then use Ka equation.
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Saj079
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#3
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(Original post by ambershell27)
You've stated units grams, then put moles in brackets? So is it mass or moles? Either way, you can calculate moles from mass and then concentration from moles (vol=1litre=1dm^3). Then use Ka equation.
Hi ,

Its is gram . could you please show the work out , really can't understand how to do this .

Thanks
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ambershell27
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#4
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#4
n=mass/Mr
concentration=n/vol
Ka=[H+][A-]/[HA]
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Saj079
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#5
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#5
(Original post by ambershell27)
n=mass/Mr
concentration=n/vol
Ka=[H+][A-]/[HA]
Thanks
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