# EDTA CalculationWatch

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#1
please can anyone help me solve this question.
An alloy of chromel containing Ni,Fe & Cr was analysed by a complexometric titration using EDTA as the titrant. The solution of the alloy was prepared by dissolving 0.7176g of alloy in HNO3 and then diluted to mark in 250cm³ volumetric flask. 50cm³ of this aliquot of the sample was treated with pyrophosphate to mark the iron and chromium. If this aliquot of the sample require 26.14cm³ of 0.058M EDTA to reach the end point with murexide as the indicator. In a second titration 50cm³ aliquot treated with hexamethylenetetraamine to mask chromium require 35.43cm³ of 0.058M EDTA to reach the end point. Finally, a third 50cm³ of aliquot was treated 50cm³ of 0.058M EDTA and back titrated with 6.21cm³ of 0.063M Cu²+ yo reach the end point with murexide indicator. Calculate the percentage of Nickel, Iron and chromium in the alloy.
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2 years ago
#2
Treat it as a simple maths question. What have you tried so far?
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#3
How?
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2 years ago
#4
You know the first titration is for Nickel. You can work out how many moles of Ni is in the sample by writing out the balanced equation for the reaction of Ni with EDTA.

You need to work out how many moles of EDTA is in 26.14ml of 0.058M. Its a simple maths problem.
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#5
Wow! I think I can get on with it from here. Thanks
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#6
I have worked out the number of moles for each analyte. How do I calculate the percentage weight for each analyte in the alloy
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2 years ago
#7
(Original post by Mo Bello)
I have worked out the number of moles for each analyte. How do I calculate the percentage weight for each analyte in the alloy
100 x mass metal/mass alloy
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