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Co-ordinate geometry question.

A circle C has centre M (6,4) and radius 3.

The diagram above shows the circle C. Thepoint T lies on the circle and the tangent at T passes through the point (12,6) The MP cuts the circle at Q

Show that TMQ is 1.0766 radians to 4 d.p.


I have the radius of MP , which is root 40, which is 6.32455532

I used Cos^-1(3/root 40) based on my workings, so I resulted in 61.68350648.

How do I know that it is 1.0766 radians?

Because I have tried division, it was not close and when I checked the mark scheme, all my values were correct.
Original post by KatheO11
A circle C has centre M (6,4) and radius 3.

The diagram above shows the circle C. Thepoint T lies on the circle and the tangent at T passes through the point (12,6) The MP cuts the circle at Q

Show that TMQ is 1.0766 radians to 4 d.p.


I have the radius of MP , which is root 40, which is 6.32455532

I used Cos^-1(3/root 40) based on my workings, so I resulted in 61.68350648.

How do I know that it is 1.0766 radians?

Because I have tried division, it was not close and when I checked the mark scheme, all my values were correct.


Change the mode.

Alternatively calculate 61.683...π180\frac{61.683...\pi}{180}
(edited 6 years ago)
Reply 2
Original post by BuryMathsTutor
Change the mode.

Alternatively calculate 61.683...π180\frac{61.683...\pi}{180}


Thank you so much!

May I ask why you have to do that though?
Original post by KatheO11
Thank you so much!

May I ask why you have to do that though?


That is how you convert between degrees and radians
Reply 4
Original post by ChallengeLover
That is how you convert between degrees and radians


Thank you!
Since one half circle is π radians (or 180°)

Original post by KatheO11
Thank you so much!

May I ask why you have to do that though?

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