The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Differentiation

The curve C has equation:
y=(x+1)(x-1)^2/x2, x>0

Find an equation of the tangent to C at the point where x = 2
Sorry you've not had any responses about this. :frown: Are you sure you've posted in the right place? :smile: Here's a link to our subject forum which should help get you more responses if you post there. :redface:
Original post by freddiek69
The curve C has equation:
y=(x+1)(x-1)^2/x2, x>0

Find an equation of the tangent to C at the point where x = 2


First you need to find the value of the y coordinate at the point where x=2.

Since you are given y as a function of x, you can find the derivative with respect to x. So you should find an expression for dy/dx.

Finally find the gradient at the point where x=2 by substituting this into the derivative expression as this would be the gradient of the tangent. You can now find an equation of the tangent at C as you know a point that lies on the line and its gradient.

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you