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Why is integration by substitution used here..

When Integrating this equation, why is substitution used and not integrating by parts?
xex2\int \:xe^{x^2}

And how can I identify when to use integrating by parts or Integration by substitution?
Original post by joyoustele
When Integrating this equation, why is substitution used and not integrating by parts?
xex2\int \:xe^{x^2}

And how can I identify when to use integrating by parts or Integration by substitution?


You won’t get anywhere with IBP (try it) and also upon inspection, we see that if we sub for x^2 then the derivative will be linear which would cancel the x next to e
Reply 2
Original post by RDKGames
You won’t get anywhere with IBP (try it) and also upon inspection, we see that if we sub for x^2 then the derivative will be linear which would cancel the x next to e


Okay, so in cases such as these step back and see which would be easiest to use, substitution or IBP.

Thanks :smile:
Original post by joyoustele
Okay, so in cases such as these step back and see which would be easiest to use, substitution or IBP.

Thanks :smile:


Yes. Without actually doing the IBP, you can tell it wont work because you can choose u=x and v’=e^x^2 but you do not know how to integrate v’. Switching the order, we can diff e^x^2 but we’ll keep integrating x to higher powers so we’ll only make the problem more complicated
Original post by joyoustele
When Integrating this equation, why is substitution used and not integrating by parts?
xex2\int \:xe^{x^2}

And how can I identify when to use integrating by parts or Integration by substitution?


I'm puzzled: why would you use a substitution? If you think about what ex2 e^{x^2} differentiates to, you can see that this is integragble by inspection.
Reply 5
Original post by Gregorius
I'm puzzled: why would you use a substitution? If you think about what ex2 e^{x^2} differentiates to, you can see that this is integragble by inspection.


I dont understand, Im sure I cannot just Isolate ex2 e^{x^2} on it's own when it is multiplied by an x x
(edited 6 years ago)
Original post by joyoustele
I dont understand, Im sure I cannot just Isolate ex2 e^{x^2} on it's own when it is multiplied by an x x


You misunderstand. What he's saying is that if you look at the derivative of ex2e^{x^2} you should notice that it's very similar to the expression you need to integrate, so just do a small change and you find your answer.
Reply 7
Original post by joyoustele
I dont understand, Im sure I cannot just Isolate ex2 e^{x^2} on it's own when it is multiplied by an x x

Consider the derivative of ex2e^{x^2} then work backwards.

Do you use inspection / pattern recognition when integrating? You can always use a substitution if you're not used to this kind of thinking, as long as you know what needs to be substituted.
Original post by joyoustele
I dont understand, Im sure I cannot just Isolate ex2 e^{x^2} on it's own when it is multiplied by an x x


What is the derivative of ex2e^{x^2}?

Hence, do you see how you can integrate your expression by inspection?
Reply 9
Original post by RDKGames
You misunderstand. What he's saying is that if you look at the derivative of ex2e^{x^2} you should notice that it's very similar to the expression you need to integrate, so just do a small change and you find your answer.


hmm Okay
One way to notice whether to use IBP or U-sub:

Notice if you consider any of the functions in the composite function, say f(x). If f'(x) cancels any other term - use U sub.

In this case

Notice if f(x)=x^2 then f'(x) = 2x which cancels nicely with the x term.
Original post by joyoustele
When Integrating this equation, why is substitution used and not integrating by parts?
xex2dx\int \:xe^{x^2}dx

And how can I identify when to use integrating by parts or Integration by substitution?


This is just
12f(x)ef(x)dx\frac{1}{2}\int \:f ' (x)e^{f(x)}dx you can use ibp if you want. (what's the derivative of e^(f(x))?)
Personally I'd use tabular integration, but I don't suppose school allow that kind of "cheating".
(edited 6 years ago)

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