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HELP PLEASE Physics Capacitance
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MrToodles4
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#1
Just a quick question 5b I don't understand:
http://pmt.physicsandmathstutor.com/...s%201%20QP.pdf
It says to find the volt across the 150 microfarad capacitor; so I did 150/600 * 6V to get 1.5V however, the markscheme says its wrong and it should be 4.5V??? Can someone please explain - many thanks
MS: http://pmt.physicsandmathstutor.com/...s%201%20MS.pdf
http://pmt.physicsandmathstutor.com/...s%201%20QP.pdf
It says to find the volt across the 150 microfarad capacitor; so I did 150/600 * 6V to get 1.5V however, the markscheme says its wrong and it should be 4.5V??? Can someone please explain - many thanks
MS: http://pmt.physicsandmathstutor.com/...s%201%20MS.pdf
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Somebody1234
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#2
Well as the MS says charge is constant is a series circuit (because current is constant) so if C=Q/V then capacitance is inversely proportional to voltage so lower capacitance=higher share of voltage
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MrToodles4
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#3
(Original post by Somebody1234)
Well as the MS says charge is constant is a series circuit (because current is constant) so if C=Q/V then capacitance is inversely proportional to voltage so lower capacitance=higher share of voltage
Well as the MS says charge is constant is a series circuit (because current is constant) so if C=Q/V then capacitance is inversely proportional to voltage so lower capacitance=higher share of voltage
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Somebody1234
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#4
(Original post by MrToodles4)
Many thanks for the reply - so is this ALWAYS the case in a series circuit with a capacitor???
Many thanks for the reply - so is this ALWAYS the case in a series circuit with a capacitor???
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MrToodles4
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#5
(Original post by Somebody1234)
I suppose so, tbh idk what exam board u do but ive never seen an edexcel question with 2 capacitors in series
I suppose so, tbh idk what exam board u do but ive never seen an edexcel question with 2 capacitors in series
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Somebody1234
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#6
(Original post by MrToodles4)
So what calculation would you use for this then? Cause mine gives the answers in the wrong way around. Its OCR A.
So what calculation would you use for this then? Cause mine gives the answers in the wrong way around. Its OCR A.
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MrToodles4
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#7
(Original post by Somebody1234)
Its all about ratios u cant really think of it as a single calculation thatll get u to the answer
Its all about ratios u cant really think of it as a single calculation thatll get u to the answer
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#8
(Original post by MrToodles4)
Alright so basically I just need to remember to swap them, so hat 1.5V i worked out would be for the high capacitance capacitor
Alright so basically I just need to remember to swap them, so hat 1.5V i worked out would be for the high capacitance capacitor
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