The square horizontal cross section of a container has side 2m. Water is poured in at the constant rate of 0.08 m^3/s and, at the same time, leaks out of a whole in the base of the container at the rate of 0.12x m^3/s, where X metres is the depth of the water in the container at time t seconds. So the volume Vm^3, of the water in the container at time t is given by V= 4x and rate of change of volume is given by: dV/dt= 0.08 - 0.12x.
Use these results to find an equation for dx/dt in terms of X, and solve this to find X in terms of t if the container is initially empty.
I have no idea where to even start, any help would be greatly appreciated.