P2 Log Questions Watch

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Bloom
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#1
Report Thread starter 14 years ago
#1
Solve the equations

a) log[2]x + 4log[x]2 = 5

b) log[3](2-3x) = log[9](6x^2 - 19x + 2)

Calculate the values of z for which

log[3]z = 4log[z]3

Can someone please help!?

Thanks
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Fermat
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#2
Report 14 years ago
#2
For a) log[2]x + 4log[x]2 = 5 you should note that log[2]x = 1/log[x]2.
Now set u = log[2]x and you have a quadratic in u which you can solve.

For b) log[3](2-3x) = log[9](6x^2 - 19x + 2), this one was done a couple of days ago. See this thread - Post #4.

For the final question, it's the same method as for a).
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