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Help with Chemistry Titrations Calculation

A student carries out a titration to determine the concentration of a solution of nitric acid. She titrates the solution of nitric acid against a standard solution of sodium hydroxide with a known concentration of 0.0998 mol/dm3. She finds that 21.80 cm3 of the nitric acid solution is needed to exactly neutralise 25.0 cm3 of the sodium hydroxide solution.
Calculate the concentration of the nitric acid solution. Give your answer to three significant figures.
The equation for the neutralisation reaction is: HNO3 + NaOH → NaNO3 + H2O (4 marks)
you already know the volume and conc of NaOH, so you find the moles using moles = conc x volume. remember you gotta convert 25cm3 into dm3, by dividing it by 1000.
then since the same number of moles of nitric acid is reacting, you find the conc using moles/volume
hope that makes sense???
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Miakat1602
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Original post by yourlocalflop
you already know the volume and conc of NaOH, so you find the moles using moles = conc x volume. remember you gotta convert 25cm3 into dm3, by dividing it by 1000.
then since the same number of moles of nitric acid is reacting, you find the conc using moles/volume
hope that makes sense???


Yes it does. Thankyou!!

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