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Trigonometry help!

So the question is:
Given that 2sin(theta)=3cos(theta), find the value of tan(theta).
Please help😂
Divide by cos⁡θ\cos \theta and use tan⁡θ=sin⁡θcos⁡θ\tan \theta = \dfrac{\sin \theta}{\cos \theta}
As Bobb has said.

Your first step in a case where your trigonometric equation involves different trig functions is to manipulate the equation to turn it into one of your identities/whatever it is you need.
(edited 6 years ago)
Original post by BobbJo
Divide by cos⁡θ\cos \theta and use tan⁡θ=sin⁡θcos⁡θ\tan \theta = \dfrac{\sin \theta}{\cos \theta}


Perhaps a little too much help for a first response?
Original post by JaredzzC
Perhaps a little too much help for a first response?


Oh, okay

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