Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    • Thread Starter
    Offline

    11
    ReputationRep:
    Attachment 722864

    need help with this question.

    Thanks
    Posted on the TSR App. Download from Apple or Google Play
    Offline

    5
    ReputationRep:
    Can't open the attachment sorry, take a pic maybe?
    Offline

    15
    ReputationRep:
    Try to visualise the circuit like a corridor, if the door is shut (switch open) you can't walk through, if there is a shut door and an open corridor then you can still walk through the open corridor.
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    11
    ReputationRep:
    (Original post by BDunlop)
    Try to visualise the circuit like a corridor, if the door is shut (switch open) you can't walk through, if there is a shut door and an open corridor then you can still walk through the open corridor.
    (Original post by BDunlop)
    Try to visualise the circuit like a corridor, if the door is shut (switch open) you can't walk through, if there is a shut door and an open corridor then you can still walk through the open corridor.
    Statement A suggests that all doors are open so why wouldn't both lamps be lit.
    Posted on the TSR App. Download from Apple or Google Play
    Offline

    15
    ReputationRep:
    (Original post by gannaspanner)
    Statement A suggests that all doors are open so why wouldn't both lamps be lit.
    Sorry, I should've been more specific.

    We can assume the internal resistance of the wire here is negligible. Because the bulb A has resistance and the wire doesn't, the electrons will flow through the route that takes the least energy, so they will go through the wire and miss out bulb A, the reasons for that I couldn't give a good explanation.
    Posted on the TSR App. Download from Apple or Google Play
    • Thread Starter
    Offline

    11
    ReputationRep:
    (Original post by BDunlop)
    Sorry, I should've been more specific.

    We can assume the internal resistance of the wire here is negligible. Because the bulb A has resistance and the wire doesn't, the electrons will flow through the route that takes the least energy, so they will go through the wire and miss out bulb A, the reasons for that I couldn't give a good explanation.
    Thanks
    Posted on the TSR App. Download from Apple or Google Play
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: February 3, 2018
Poll
Do you agree with the proposed ban on plastic straws and cotton buds?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.