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1. Is anyone willing to help me answer the following question. I find it really hard and am struggling. Hope someone has time to help!
2. (Original post by Studentttt101)
Is anyone willing to help me answer the following question. I find it really hard and am struggling. Hope someone has time to help!
The diagonals of a rhombus intersect at right angles.

And it goes through A, so its equation is?
3. I don’t really get what you mean. Do you know how to work it out or the answer?
4. (Original post by Studentttt101)
I don’t really get what you mean. Do you know how to work it out or the answer?
We don't do questions for you - you've been given hints.
5. I had this question on a practise paper. I can’t answer it for you - however, if you join points A and C you get an X shape, splitting the rhombus into 4 triangles. The angles in the X will all be 90°, adding up to the standard 360°. You can use that.
6. Isnt the answer meant to be an equation not an angle?
7. (Original post by Studentttt101)
...
What I gave you are the steps required to solve the problem.

You should know that if two lines intersect at right angles then the product of their gradients is -1. You also should know how to find the equation of a line, given a point on it and its gradient.
8. You use y = mx+ c?
9. (Original post by Studentttt101)
You use y = mx+ c?
That's one way. Just substitute the point A's coordinates for x,y and knowing m, you can work out c. Done.
10. (Original post by Studentttt101)
You use y = mx+ c?
This is something you don't seem to know but need to remember:
All the points on a line satisfy its equation.

The reverse of this can be used to discover a -intercept using its gradient and a point on it.

if , . Therefore if you know a point on the line, .
Hence, you have worked out the equation of the line.

To solve this equation find and then use what I explained to work out . The diagonals of a rhomus perpendicularly intersect.

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