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# Trig harmonic form question watch

1. Write down the minimum and maximum value of the equation
(3sin(x)+2cos(x))^2
My first thought was to work this out subbing in values and I got that when x=180, the equation would equal 4. However using the form I converted it to, root13 sin(x)(x-33.7), the minimum is 13.
Which method is correct? And then I get the max to be 13 as well but how can the min and max be the same?
2. Firstly I would combine the two to get a single trig function then consider the maximum. The max would therefore be 13.

The min is a bit trickier though: it's not just -root 13 squared, the minimum value is 0^2 = 0.
3. (Original post by thekidwhogames)
Firstly I would combine the two to get a single trig function then consider the maximum. The max would therefore be root 13.

The min is a bit trickier though: it's not just -root 13 squared, the minimum value is 0^2 = 0.
How is the max root 13 when it is then being squared?
4. (Original post by ElDonCorleone)
How is the max root 13 when it is then being squared?
Sorry I made a typo. The max is root 13 squared i.e. max = 13. The min = 0.

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Updated: February 3, 2018
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