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    Any ideas or starting points?
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    (Original post by Y11_Maths)
    Any ideas or starting points?
    What's the probability of landing on each number??

    Then, what are the possible combinations to get a total score of 4?
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    So there are 4 combinations that would get a total score of 4: 2&2 2&2 1&3 3&1
    How do I work out the probability of landing on each number? P(1) is x/360?
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    (Original post by Y11_Maths)
    So there are 4 combinations that would get a total score of 4: 2&2 2&2 1&3 3&1
    How do I work out the probability of landing on each number? P(1) is x/360?
    No there are only 3. You don't count 2&2 twice since different order produces the same branch if you consider the tree diagram.

    And yes, x/360 is the probability of landing on 1 on a given spin
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    (Original post by RDKGames)
    No there are only 3. You don't count 2&2 twice since different order produces the same branch if you consider the tree diagram.

    And yes, x/360 is the probability of landing on 1 on a given spin
    Ok so I know the probability of getting a 1 or 2 but how do I do it for 3? Is it 360-3x all divided by 360? But that equals 1-3x/360 no?
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    (Original post by Y11_Maths)
    Ok so I know the probability of getting a 1 or 2 but how do I do it for 3? Is it 360-3x all divided by 360? But that equals 1-3x/360 no?
    Yes, that's right.
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    (Original post by RDKGames)
    Yes, that's right.
    Am I on the right track?
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    (Original post by Y11_Maths)
    Am I on the right track?
    Probabilities are multiplied, THEN all 3 are added together to give 16/81
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    (Original post by RDKGames)
    Probabilities are multiplied, THEN all 3 are added together to give 16/81
    Oh right I think I get it
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    (Original post by RDKGames)
    Probabilities are multiplied, THEN all 3 are added together to give 16/81
    Is this correct?
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    (Original post by Y11_Maths)
    Is this correct?
    No, \mathbb{P}(3) = \dfrac{360-3x}{360} = 1-\dfrac{3x}{360} \neq \dfrac{1-3x}{360}
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    (Original post by RDKGames)
    No, \mathbb{P}(3) = \dfrac{360-3x}{360} = 1-\dfrac{3x}{360} \neq \dfrac{1-3x}{360}
    I’m on the app so this code makes no sense to me
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    (Original post by Y11_Maths)
    I’m on the app so this code makes no sense to me
    I recommend you use a computer when asking for maths help because 'this code stuff' is very useful.

    My post:

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    (Original post by RDKGames)
    I recommend you use a computer when asking for maths help because 'this code stuff' is very useful.

    My post:

    Ok noted for future references, and I see where I went wrong thanks. Is everything else I did correct though? Solve for x through a quadratic?
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    (Original post by Y11_Maths)
    Ok noted for future references, and I see where I went wrong thanks. Is everything else I did correct though? Solve for x through a quadratic?
    The actual method is fine, yes, though there are silly errors like not squaring 360 on the denominator on the 2+2 case
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    (Original post by RDKGames)
    The actual method is fine, yes, though there are silly errors like not squaring 360 on the denominator on the 2+2 case
    I did it on my calculator then got distracted 😂. Thanks for the help mate
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    (Original post by RDKGames)
    The actual method is fine, yes, though there are silly errors like not squaring 360 on the denominator on the 2+2 case
    I feel like I’ve gone wrong because I don’t think x can be 40 degrees can it?
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    (Original post by Y11_Maths)
    I feel like I’ve gone wrong because I don’t think x can be 40 degrees can it?
    Why can't it...?

    Also check your b^2-4ac term.
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    (Original post by RDKGames)
    Why can't it...?

    Also check your b^2-4ac term.
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    40*3= 120 which is less than 180 degrees. I just thought it was inaccurate, but it probably isn’t drawn accurately tbf
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    I got the answer as x=32.60291625 degrees
 
 
 
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