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    Sin((pi/3)-y)=cos(y+(5pi/6))

    I expand this as normal but then I get to a point where I have tan(y)=0/0 which is obviously indeterminate and whichever way I go, I always end up with this? Where have I gone wrong? Will attach full working
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    (Original post by ElDonCorleone)
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    Your working should lead to \tan y=-\dfrac{\sqrt 3}{0}.

    So \tan y is undefined.

    \tan y is undefined when \cos y=0 since \tan y = \dfrac{\sin y}{\cos y}. So \tan y is undefined at \dfrac{\pi}{2} + n \pi.
 
 
 
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