Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta
    • Thread Starter
    Offline

    10
    ReputationRep:
    Im quite confused on how acceleration is max at the amplitude for a SHM oscillator? I always though the acceleration would be max as it passes through the equilibrium position, due to the biggest change in velocity happening there. However from the equation a=-w^2x where w is omega, the acceleration is max when x = A, and im not sure why? could anyone help explain it to me please.
    Offline

    12
    ReputationRep:
    The force is proportional and in the opposite direction (by F = -kx), hence as x increases F will also increase, and since the mass is constant the acceleration increases too (F = -kx = ma). The velocity is maximum as it passes through the eq. position and the acceleration is zero, since the displacement is zero.
    Offline

    9
    ReputationRep:
    Acceleration is proportional to force, from Newton's 2nd Law.
    And the force is greatest when you're at the biggest displacement from the equilibrium position, therefore that's where the max acceleration is too.

    Does this help?
    • Thread Starter
    Offline

    10
    ReputationRep:
    Yes thank you both, explaining it in terms of force made it click for me. Thanks for taking the time to help me
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: February 5, 2018
Poll
Do I go to The Streets tomorrow night?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.