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# Graphs and resistivty watch

1. Not sure about second part of this question:

Current I through a wire of resistivity p varies with length L, area of cross-section A and pd V in accordance with the equation I = VA/pL.

Sketch a graph of I against a) V , b) L , c) 1/L

Explain how you would determine the resistivity from the graph of I against a) V b) 1/L

So the graph of I against V is a straight line graph where the gradient = A/pL.
Can resistivity be found by calculating the gradient and rearranging to get p = AL/gradient?

And the graph of I against 1/L is a straight line graph with gradient = VA/p and you could rearrange this to get p = VA/gradient but V isn't a constant so how would it work?

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Updated: February 5, 2018
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