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Redox equations

I’m so stuck and confused on this question:

4F) give two half equations for his reaction; oxidation and reduction.

Al + O2 —> Al2O3

What I got:
Al2 —> Al2^+6 + 6e-
O3 + 6e- —> 3O^-2

Is this correct??

Reply 1

charco

Study Forum Helper

Original post by Sebastian1299

No, you have not even copied the species used correctly.

On the left hand side it is oxygen gas, O₂ and on the right hand side it is the oxide ion, O^2-.

Now you have to balance:

O₂ + 4e --> 2O^2-

Now do the same for aluminium ...