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    I’m so stuck and confused on this question:

    4F) give two half equations for his reaction; oxidation and reduction.

    Al + O2 —> Al2O3

    What I got:
    Al2 —> Al2^+6 + 6e-
    O3 + 6e- —> 3O^-2

    Is this correct??
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    (Original post by Sebastian1299)
    I’m so stuck and confused on this question:

    4F) give two half equations for his reaction; oxidation and reduction.

    Al + O2 —> Al2O3

    What I got:
    Al2 —> Al2^+6 + 6e-
    O3 + 6e- —> 3O^-2

    Is this correct??
    No, you have not even copied the species used correctly.

    On the left hand side it is oxygen gas, O2 and on the right hand side it is the oxide ion, O2-.

    Now you have to balance:

    O2 + 4e --> 2O2-

    Now do the same for aluminium ...
 
 
 
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