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    Please can someone help me with 6b) on this paper. I understand the reflection but don't see where the translation with pi affects the answer.. I would have moved it up by pi, so the intercept was at 3pi/2 rather than pi/2?

    Thanks

    paper: http://filestore.aqa.org.uk/sample-p...3-QP-JUN13.PDF

    mark scheme: http://filestore.aqa.org.uk/sample-p...W-MS-JUN13.PDF
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    (Original post by jazz_xox_)
    Please can someone help me with 6b) on this paper. I understand the reflection but don't see where the translation with pi affects the answer.. I would have moved it up by pi, so the intercept was at 3pi/2 rather than pi/2?

    Thanks

    paper: http://filestore.aqa.org.uk/sample-p...3-QP-JUN13.PDF

    mark scheme: http://filestore.aqa.org.uk/sample-p...W-MS-JUN13.PDF
    You reflect it in the x-axis axis, so the new intercept is -pi/2. Moving it up by pi gives pi/2 as the intercept and thus the diagram.
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    (Original post by RDKGames)
    You reflect it in the x-axis axis, so the new intercept is -pi/2. Moving it up by pi gives pi/2 as the intercept and thus the diagram.
    Thank you
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    (Original post by RDKGames)
    You reflect it in the x-axis axis, so the new intercept is -pi/2. Moving it up by pi gives pi/2 as the intercept and thus the diagram.
    Wait sorry, is it reflected in the x or y axis? From the mark scheme it looks as if it's reflected in y?

    If the - sign is in front of the whole function is this y or x? I keep confusing myself over the last few days!

    Edit: I now get that it's reflected in the x-axis, but it just looks to me as if the diagram on the mark scheme is reflected in the y-axis?
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    (Original post by jazz_xox_)
    Wait sorry, is it reflected in the x or y axis? From the mark scheme it looks as if it's reflected in y?

    If the - sign is in front of the whole function is this y or x? I keep confusing myself over the last few days!

    Edit: I now get that it's reflected in the x-axis, but it just looks to me as if the diagram on the mark scheme is reflected in the y-axis?
    Yes refl. in x axis + translation by pi is just another way of obtaining the graph that is a refl in y axis
 
 
 
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