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    im very tired so I could be being stupid but how is velocity (v) a function displacement (s)?

    I know you differentiate v to get s and integrate s to get v.
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    (Original post by Maths&physics)
    I know you differentiate v to get s and integrate s to get v.
    It's the other way round.
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    (Original post by RDKGames)
    It's the other way round.
    according to the tutorial, v = f (s) : v is a function of displacement. what does that mean? btw, ive not slept in over 24 hours - long story, and I dont plan to make a habit out of it.
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    (Original post by Maths&physics)
    according to the tutorial, v = f (s) : v is a function of displacement. what does that mean? btw, ive not slept in over 24 hours - long story, and I dont plan to make a habit out of it.
    Generally, velocity is a function time. But if you can express v in terms of s then it can be a function of displacement as well.

    For example, if s(t)=e^{2t} then v(t)=2e^{2t} hence v(s) = 2s

    It means that if you only know your displacement at some time, but you do not know the time, then you can still determine its velocity at that point, since velocity is only dependent on displacement in such cases.
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    (Original post by RDKGames)
    Generally, velocity is a function time. But if you can express v in terms of s then it can be a function of displacement as well.

    For example, if s(t)=e^{2t} then v(t)=2e^{2t} hence v(s) = 2s

    It means that if you only know your displacement at some time, but you do not know the time, then you can still determine its velocity at that point, since velocity is only dependent on displacement in such cases.
    did you differentiate: s(t) to get 2e^2t ???
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    (Original post by Maths&physics)
    did you differentiate: s(t) to get 2e^2t ???
    Yes...

    v(t) = \dfrac{d}{dt} s(t)
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    (Original post by RDKGames)
    Yes...

    v(t) = \dfrac{d}{dt} s(t)
    thanks. I think I should go over it tomorrow once ive slept.
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    (Original post by RDKGames)
    Yes...

    v(t) = \dfrac{d}{dt} s(t)
    ok, I get that but what does dv/ds give you?
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    (Original post by Maths&physics)
    ok, I get that but what does dv/ds give you?
    \dfrac{dv}{ds} = \dfrac{\frac{dv}{dt}}{\frac{ds}{  dt}} = \dfrac{a}{v}

    Where s,v,a are all functions of time.
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    (Original post by RDKGames)
    \dfrac{dv}{ds} = \dfrac{\frac{dv}{dt}}{\frac{ds}{  dt}} = \dfrac{a}{v}

    Where s,v,a are all functions of time.
    a / v = ?
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    (Original post by Maths&physics)
    a / v = ?
    That's it, I'm not sure what you are looking for
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    (Original post by RDKGames)
    That's it, I'm not sure what you are looking for
    Ok, it doesn’t equal time or displacement?
 
 
 
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