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# GCSE Straight Line Graphs watch

1. can some1 help me tthis questiion pls
Give the full coordinate of the point where the line y =5x−3 crosses the x-axis.
2. Make a table like this:

x |-2 -1 0 1 2 3 4 5 etc.
---|------------------------------
y | <----- fill in the numbers for y using equation

Fill in the table using the equation y=5x-3

Where does it cross the x axis?

I hope this makes sense and helps
3. (Original post by laurawatt)
Make a table like this:

x | 0 1 2 3 4 5
---|------------------------------
y | <----- all in the numbers for y using equation

Fill in the table using the equation y=5x-3

Where does it cross the x axis? If you put the numbers in the table into coordinates, then when does it look like this (0,_) with the 0 in the X axis?

I hope this makes sense and helps
i remember this< wait let me try thnks
4. (Original post by laurawatt)
Make a table like this:

x |-2 -1 0 1 2 3 4 5 etc.
---|------------------------------
y | <----- fill in the numbers for y using equation

Fill in the table using the equation y=5x-3

Where does it cross the x axis?

I hope this makes sense and helps
5. (Original post by error405)
can some1 help me tthis questiion pls
Give the full coordinate of the point where the line y =5x−3 crosses the x-axis.
The line crosses the x-axis when y=0.

So solve 5x-3=0
6. (Original post by BobbJo)
The line crosses the x-axis when y=0.

So solve 5x-3=0
x=3/5 so (3/5,0) thanks
7. (Original post by error405)
good! So now you know that 0 for the y has to be between 0 and 1 for the x

so 5x-3=0
so divide by 5 to get x by itself.
x-(3/5)=0
so then plus 3/5 to 0 to get the x on one side
this means that the line crosses the x axis at (0.6,0) which is the same as (3/5, 0)
8. (Original post by laurawatt)
good! So now you know that 0 for the y has to be between 0 and 1 for the x

so 5x-3=0
so divide by 5 to get x by itself.
x-(3/5)=0
so then plus 3/5 to 0 to get the x on one side
this means that the line crosses the x axis at (0.6,0) which is the same as (3/5, 0)
ttthanks

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