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# Integration maths help pleasee watch

1. Hi guys, so I don't get part iv) only. Can someone please help me here? Is there are formula that I need to know for this?
2. (Original post by sienna2266)
Hi guys, so I don't get part iv) only. Can someone please help me here? Is there are formula that I need to know for this?

The 'inverse' of is just a reflection of in the line y=x. To find this, you swap x and y in its equation. Now the same thing happens to the gradient. You get turns into and this is the gradient function of

So really, where
3. (Original post by RDKGames)
The 'inverse' of is just a reflection of in the line y=x. To find this, you swap x and y in its equation. Now the same thing happens to the gradient. You get turns into and this is the gradient function of

So really, where
Thanks so much!

Is my working out correct here?
So here, at point (1,4) of y=f(x), the gradient is 60 and at point (4,1) of y=f^-1(x), the gradient is 1/60 ?
Also, is there a quicker/alternative way to do this assuming that I've got the correct working out here?

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Updated: February 8, 2018
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