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# Random integration question. watch

1. I bump into this question was wondering if I got it right.

Let =
,Therefore =
Since,

We will re-define the boundaries later.
Integrating we get:

Re-defining the boundaries;
Since, =
Where
,
Hence,
Substituting then subtracting, I need up with
Point out the mistake(s), If found.
2. (Original post by Darke1231)
I bump into this question was wondering if I got it right.
Where is it?
3. (Original post by RDKGames)
Where is it?
Just posted it.
4. It would probably be easier to just sketch the graph and work out the areas from that - I think the answer is 1? Not sure about that though
Edit - from the graph below you can see it's 1
5. (Original post by Darke1231)
...
This is incorrect. (mostly your assumption on how to differentiate a modulus function)

Use the fact that on and on
6. (Original post by RDKGames)
This is incorrect. (mostly your assumption on how to differentiate a modulus function)

Use the fact that on and on
Knew I was missing something, I see. How will I continue then? Integrating them in separate?
7. (Original post by Darke1231)
Knew I was missing something, I see. How will I continue then? Integrating them in separate?
yes
8. (Original post by PuffyPenguin)
It would probably be easier to just sketch the graph and work out the areas from that - I think the answer is 1? Not sure about that though
Edit - from the graph below you can see it's 1
I see, Thanks.
9. (Original post by RDKGames)
yes
+ ???
10. (Original post by Darke1231)
+ ???
No, the first one from 0 to 1 and the second from 1 to 2
11. (Original post by RDKGames)
No, the first one from 0 to 1 and the second from 1 to 2
Got it, cheers,mate.
12. (Original post by Darke1231)
I bump into this question was wondering if I got it right.
Puffy Penguin's approach is the better one here.

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