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1. A ball is thrown horizontally from the top of a building.
The ball is thrown with a horizontal speed of 8.2 m s-1. At point P on the trajectory, the ball is a
distance x from the building and is moving at an angle of 60o
to the horizontal. Air resistance is
negligible. For the ball at point P:
i) show that the vertical component of its velocity is 14.2 m s-1

Okay so using trigonometry I did Sin(60)*8.2 to find the vertical component but my answer was 7.1 which is exactly half of the answer I need so I would assume I need to multiply by 2 but I'm not sure why or if I've just done it wrong

Could someone help thanks
2. Draw a diagram to see what’s going on.
3. (Original post by Connor09)
Draw a diagram to see what’s going on.
Sorry there was a diagram with the question I thought it uploaded here it is
Attached Images

4. Okay great, now what made you use sin? You’re right in using trigonometry.
5. (Original post by Connor09)
Okay great, now what made you use sin? You’re right in using trigonometry.
I need the opposite side and I have the hypotenuse so O=sin(x) *H
6. Do you have the hypotenuse? You are given the horizontal.
7. (Original post by Connor09)
Do you have the hypotenuse? You are given the horizontal.
Oooohhhh *facepalms* yeah no I don't I have the adjacent so I shouldve used tan
8. Correct!

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