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    “A point P lies on the line y= 4-3x. The point p is a distance squared root 34 from the origin. Find two possible positions of P.” I dont get this at all, it doesnt come with a diagram just a worded question
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    (Original post by Luciehkd)
    “A point P lies on the line y= 4-3x. The point p is a distance squared root 34 from the origin. Find two possible positions of P.” I dont get this at all, it doesnt come with a diagram just a worded question
    If it lies on that line at x=p, then it has coordinates (p,4-3p). So, what is the distance of it from the origin in terms of p? This is just applying Pythagoras' Theorem.
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    (Original post by Luciehkd)
    “A point P lies on the line y= 4-3x. The point p is a distance squared root 34 from the origin. Find two possible positions of P.” I dont get this at all, it doesnt come with a diagram just a worded question
    Sketch the line, marking where it crosses the axes. Now draw a circle of radius ~6 (so that you get the intersections in approximately the right locations), centered on the origin. This should show you (approximately) the two points that you're after.

    The maths is actually a little simpler. Any point on the line can be written as (x, 4-3x). Can you write a formula for the distance from the origin to that generic point? Solve for that being root 34.

    Please post your workign if you have any issues.
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    It cant be, its not a right angled triangle.. im so confused
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    (Original post by Luciehkd)
    “A point P lies on the line y= 4-3x. The point p is a distance squared root 34 from the origin. Find two possible positions of P.” I dont get this at all, it doesnt come with a diagram just a worded question
    Answer is p( 3 ; -5) and (-3/5 ; 29/5)
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    (Original post by Luciehkd)
    It cant be, its not a right angled triangle.. im so confused
    Red line is y=4-3x

    The purple line is the line whose length you're looking for.

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    (Original post by Rockers.)
    Answer is p( 3 ; -5) and (-3/5 ; 29/5)
    Thank you, would you please explain how you got this. If its not too much to ask?
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    (Original post by Rockers.)
    Answer is
    Please don't post answers. The intention is to help posters understand how to tackle problems.
 
 
 
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