The question is
Differentiate: y= 2e^(2x+1)
The answer is dy/dx = 4e^2x+1
please can anyone provide me with the working out to that answer step by step?
I'm not able to solve this one it's doesn't seem as straightforward as the others I've done
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Help: chain rule question differenetiation watch
- Thread Starter
- 09-02-2018 23:01
- 09-02-2018 23:05
Differentiate the power (2x+1) this leaves you with 2. Multiply this by 2e^(2x+1) which leaves you with 4e^(2x+1).
explanation below:Last edited by Ben_171; 09-02-2018 at 23:08.
- 09-02-2018 23:06
let u = 2x+1, du/dx = 2.
you now have y = 2e^u
we know that dy/du = 2e^u
dy/dx = dy/du * du/dx (since the dus cancel)