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# Forces in equilibrium - Mechanics watch

1. https://imgur.com/a/Dvxn3

There are three masses in this diagram of 90, 60 and 120g respectively strung from pulleys on a force board. The 90g mass is at 60 degrees to the horizontal, the 60g one is at 40 degrees and the 120g mass goes directly down, having no horizontal component.

How do I work out the horizontal and vertical components if the system is in equilibirum?
2. (Original post by Echtebilbo)
https://imgur.com/a/Dvxn3

There are three masses in this diagram of 90, 60 and 120g respectively strung from pulleys on a force board. The 90g mass is at 60 degrees to the horizontal, the 60g one is at 40 degrees and the 120g mass goes directly down, having no horizontal component.

How do I work out the horizontal and vertical components if the system is in equilibirum?
I'm struggling to see how this system can be in equilibrium. What's the complete question?
3. You need to work out the vertical and horizontal tension forced and equate them to the applied weights. Do you know how to do that, or do you need more help?
4. (Original post by Echtebilbo)
https://imgur.com/a/Dvxn3

There are three masses in this diagram of 90, 60 and 120g respectively strung from pulleys on a force board. The 90g mass is at 60 degrees to the horizontal, the 60g one is at 40 degrees and the 120g mass goes directly down, having no horizontal component.

How do I work out the horizontal and vertical components if the system is in equilibirum?
You use trigonometry on the tensions treating them as completely separate.

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