smeagol19
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Report Thread starter 2 years ago
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Hey!
I'm a little stumped over this question so I would really appreciate any advice/answers!

i)What is the ammeter reading
ii)What is the resistance for the bulb
iii)What is the power for the bulb and resistor
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Joinedup
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Hi - it's better to attach picture format files than word docs.

PD across the 10 ohm resistor is 5V
I=V/R
so the current through the 10 ohm resistor is 5/10 Amps

PD across the bulb plus the 5V across the resistor must equal the PD of the battery (6V)

Power is VI - both the bulb and resistor carry the same current because they are in series.
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smeagol19
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Sorry about the image - noted for future reference
Thank you so much for your help!!
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