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    Hey!
    I'm a little stumped over this question so I would really appreciate any advice/answers!

    i)What is the ammeter reading
    ii)What is the resistance for the bulb
    iii)What is the power for the bulb and resistor
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    Hi - it's better to attach picture format files than word docs.

    PD across the 10 ohm resistor is 5V
    I=V/R
    so the current through the 10 ohm resistor is 5/10 Amps

    PD across the bulb plus the 5V across the resistor must equal the PD of the battery (6V)

    Power is VI - both the bulb and resistor carry the same current because they are in series.
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    Sorry about the image - noted for future reference
    Thank you so much for your help!!
 
 
 
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