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# Circuits help please! watch

1. Hey!
I'm a little stumped over this question so I would really appreciate any advice/answers!

i)What is the ammeter reading
ii)What is the resistance for the bulb
iii)What is the power for the bulb and resistor
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2. qwe.docx (142.6 KB, 21 views)
3. Hi there,
I've moved your thread to the Physics forum where hopefully someone will be able to answer your question
4. Don't you need ii for i?
5. (Original post by smeagol19)
Hey!
I'm a little stumped over this question so I would really appreciate any advice/answers!

i)What is the ammeter reading
ii)What is the resistance for the bulb
iii)What is the power for the bulb and resistor
Ohms law I = V/R

Work out the current through the 10 Ohms resistor first.

Current in a series path is the same at every point.

Meaning, the current through the lamp must be the same as that flowing through the resistor.

The voltage drops in the series path must sum to the supply voltage.

Calculate the voltage dropped across the lamp.

Finally using Ohms law again, calculate the lamp resistance.

Power P = V x I
6. Thank you so much! I think i get it now

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