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    Hi,

    Can someone tell and explain the best way to tackle this C2 question? I was going to expand everything but thought that would take too long, so was wondering if there is an easier and shorter way of doing it, especially part (a)!

    Thanks!
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    (Original post by DhylanP - CRGS)
    Hi,

    Can someone tell and explain the best way to tackle this C2 question? I was going to expand everything but thought that would take too long, so was wondering if there is an easier and shorter way of doing it, especially part (a)!

    Thanks!
    You’ll need to expand (2+x)^5 in the normal way to get the constant, x^2 and x^4 terms but once you’ve done this there isn’t much more work. For (2-x)^5 that’s the same expansion but with x->-x. So the constant, x^2 and x^4 terms will be the same as in the expansion (2+x)^5.

    So it’s just a case of expanding one bracket and then doubling the coefficients.
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    once you have found A,B,C... for instance A = -3 B = -11 and C = 8 *FOR ILLUSTRATION ONLY*

    then the RHS will be

    8x4 - 11x2 - 3

    then for part b)

    8x4 - 11x2 - 3 = 349
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    Hi,

    Would it be best to use the binomial expansion formula and expand to obtain the first 5 terms?
 
 
 
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