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    ____1_____
    X^2(2X-1)

    Can somone show me the full steps to this question please
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    (Original post by gogetta)
    ____1_____
    X^2(2X-1)

    Can somone show me the full steps to this question please
    It decomposes into the form A/x + B/(x^2) + C/(2x-1)

    Find A,B and C
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    (Original post by RDKGames)
    It decomposes into the form A/x + B/(x^2) + C/(2x-1)

    Find A,B and C
    thx for the reply, i know but i want to when finding c
    why is the equation

    0=a+2c

    and not 1=a+2c when it suppose to be this one.

    so why 0 and not 1

    also to confirm is a= 4 and b=-1
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    (Original post by gogetta)
    thx for the reply, i know but i want to when finding c
    why is the equation

    0=a+2c

    and not 1=a+2c when it suppose to be this one.

    so why 0 and not 1

    also to confirm is a= 4 and b=-1
    Getting the fractions as one, you should get (Ax+B)(2x-1)+C(x^2) as the numerator, which expands into (2A+C)x^2+(2B-A)x-B

    Clearly, there should be no x^2 or x term in the numerator, so we set 2A+C=0.
    Similarly, 2B-A=0.
 
 
 
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