A particle P passes through point A with velocity 2.8ms-1 and the constant acceleration 0.12ms-2. Three seconds later, a second particle Q passes through A with velocity 2.4ms-2 and constant acceleration 0.2ms-2.
Show that on the point meet, 2t2-50t-315=0. Where t is the time after P passes through A.
My following working:
Insert into equation: S=UT+1/2AT2
=> Q is S=0.1t2+2.4t
and P is S=0.06t2+3.16t+8.94
As to have both equal
Which meant that I must be wrong somewhere, but I can't seem to find the mistake.
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Help, can anyone tell me my mistakes on this mechanics question? watch
- Thread Starter
- 15-02-2018 20:32
- 15-02-2018 20:57
Edit: You made a calculation error for P, the value independent of t (8.94) is wrong.Last edited by username3684524; 15-02-2018 at 21:05.
- 15-02-2018 21:15
By on point meet do you mean when the two particles meet or what?
- 25-03-2018 18:20
The time for P is just t, meaning Q is t-3
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- Community Assistant
- Study Helper
- 25-03-2018 18:28