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Distance travelled from displacement equation watch

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    How can I find the distance travelled given the equation for displacement and velocity between the values t=0 and t=6.62

    t>=0
    v = 8t-2/3t^3
    s = t^2-1/3t^3+8t

    I tried subbing 6.62 into the displacement equation and I got 0 (which is not the correct answer). Both 0 and 6.62 are roots of the displacement equation.

    UPDATE: Integrating the velocity equation between 0 and 6.62 results in -144.80 (which is not the right answer; +144.8 is not as well)
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    What is the full text of the original question?
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    (Original post by old_engineer)
    What is the full text of the original question?
    This is the full question.
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    (Original post by Kartheyan)
    This is the full question.
    Well something doesn't add up as your expressions for displacement and velocity don't correspond to one another via differentiation / integration.
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    It's probably because he stops then starts going in the opposite direction. Maybe try finding the times at which he has 0 velocity, at that time he is just about to turn and drive the other way. Then break the whole journey into smaller sections.
 
 
 
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Updated: February 16, 2018
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