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# Distance travelled from displacement equation watch

1. How can I find the distance travelled given the equation for displacement and velocity between the values t=0 and t=6.62

t>=0
v = 8t-2/3t^3
s = t^2-1/3t^3+8t

I tried subbing 6.62 into the displacement equation and I got 0 (which is not the correct answer). Both 0 and 6.62 are roots of the displacement equation.

UPDATE: Integrating the velocity equation between 0 and 6.62 results in -144.80 (which is not the right answer; +144.8 is not as well)
2. BUMP
3. What is the full text of the original question?
4. (Original post by old_engineer)
What is the full text of the original question?
This is the full question.
5. (Original post by Kartheyan)
This is the full question.
Well something doesn't add up as your expressions for displacement and velocity don't correspond to one another via differentiation / integration.
6. It's probably because he stops then starts going in the opposite direction. Maybe try finding the times at which he has 0 velocity, at that time he is just about to turn and drive the other way. Then break the whole journey into smaller sections.

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