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1. Does anybody know how to solve the question:

Given that 9^a = 2 , What are the possible values of 27^a ?

Any help would be highly appreciated. Thanks in advance!
2. 9 = 3^2
27 = 3^3
Hope this helps.
3. Log log log
4. This can be done one of two ways, usually with this type of question you are supposed to take logs to solve it so, I would take logs of 9^a=2 to the base 2 so log2(9^a)=1 as 2^1=2, now we use laws of logs to get a*log2(9)=1 (* represents multiplication) and then rearrange this, giving a=1/(log2(9)) now you just type 27^(1/(log2(9))) into the calculator and it gives 2.8284... as the answer.
However as this is a GCSE question and the numbers are nice, it can be done another way, change the 9 and 27 into powers of 3 so we get 3^(2a)=2 and the question is asking for 3^(3a) now if we square root the first one then we reduce the power of 3 so we get 3^a=2^(1/2)=squareRoot(2) now to get 3^(3a) we just need to cube the answer so we get 3^(3a)=27^a=2^(3/4)=squareRoot(2)^3 which gives 2.8284... when entered into the calculator.

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