Turn on thread page Beta
    • Thread Starter

    The question is to find the isospin coupling of a pion(+), pion(-) and a pion(0) by deriving the isospin function.

    I obtain the answer:
    sqrt(1/10)|3 0> + ((3-sqrt(3))/6)|2 0> +((sqrt(30)-5sqrt(2))/10)*|1 0>+ sqrt(6)/6 *|0 0>
    But this doesn't seem right as the coefficients squared do not add up to 1. Did I take the right approach or am I doing it wrong?

    My method:

    So this is what I did: I found |1 -1>|1 0>=sqrt(1/2)(|2 -1> -|1 -1> ) by reading off the CG table.
    Then to find |1 1>|1 -1>|1 0>, I did |1 1>|1 -1>|1 0>=sqrt(1/2)(|2 -1>|1 1> -|1 -1>|1 1> )by multiplying the line before by |1 1>
    So I found |2 -1>|1 1>=sqrt(1/5)|3 0>-sqrt(1/2)|2 0>+sqrt(3/10)*|1 0>
    And also |1 -1>|1 1>=sqrt(1/6)|2 0>-sqrt(1/2)|1 0>+sqrt(1/3)*|0 0>
    Hence, after simplifying down I end up with the answer above
The home of Results and Clearing


people online now


students helped last year

University open days

  1. Bournemouth University
    Clearing Open Day Undergraduate
    Fri, 17 Aug '18
  2. University of Bolton
    Undergraduate Open Day Undergraduate
    Fri, 17 Aug '18
  3. Bishop Grosseteste University
    All Courses Undergraduate
    Fri, 17 Aug '18
Will you be tempted to trade up and get out of your firm offer on results day?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.