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# What does this question mean? Mechanics watch

1. Just wanted to know what part c of this question means? It's worded in a very bizarre way! Many thanks
2. part c asks for the time between the moment when sphere is first at p and when it passes p again after the string breaks. (does it make sense now??)
3. Is it just asking you to find the time between the sphere beginning to move upwards, and the time it returns to P? I see they've given you a quadratic with T defined after the string breaks, which means at T = 0, the sphere is 1.8m above P - this is probably an important clue?
4. (Original post by Brudor2000)
part c asks for the time between the moment when sphere is first at p and when it passes p again after the string breaks. (does it make sense now??)
Thank you so much! Now how do you go about doing this question?
5. (Original post by plklupu)
Is it just asking you to find the time between the sphere beginning to move upwards, and the time it returns to P? I see they've given you a quadratic with T defined after the string breaks, which means at T = 0, the sphere is 1.8m above P - this is probably an important clue?

Thank you so much! Now how do you go about doing this question?
6. to find time after string breaks use the quadratic equation given in b. then u need to find time when sphere is at p for first time to when the string breaks ( i am trying to figure that out). then just add both the times together to get total time.
7. (Original post by Brudor2000)
to find time after string breaks use the quadratic equation given in b. then u need to find time when sphere is at p for first time to when the string breaks ( i am trying to figure that out). then just add both the times together to get total time.
Thank you! I'll give that a go now too!
8. (Original post by h26)
Thank you so much! Now how do you go about doing this question?
My gut instinct is that it's just the value of T + however long it took to travel 1.8m up in the first place, but that seems way too simple for 4 marks. I think you need to use the acceleration from part iv) for that initial 1.8m bit.
9. Damn, @Brudor2000 is beating me to it, haha!
10. (Original post by plklupu)
Damn, @Brudor2000 is beating me to it, haha!
@plklupu lol
11. I got 1.99s in total - have you got a mark scheme where you can check?
12. (Original post by plklupu)
I got 1.99s in total - have you got a mark scheme where you can check?
It's 2.19 seconds - actually it's not

Edit: actually ill double check the time
13. (Original post by plklupu)
I got 1.99s in total - have you got a mark scheme where you can check?
Here is the link to the paper to save time:
http://mei.org.uk/files/papers/m109ju_livn.pdf
14. (Original post by h26)
It's 2.19 seconds but ill post the mark scheme as well

Edit: actually ill double check the time
Oops, I ****ed up me acceleration for the initial 1.8m - I wrote down 3ms^-2, but it's 2.5. You're right about 2.19s.
15. (Original post by plklupu)
I got 1.99s in total - have you got a mark scheme where you can check?
http://mei.org.uk/files/papers/m109ju_livn.pdf
here is the link to mark scheme. have a look at it
16. (Original post by plklupu)
Oops, I ****ed up me acceleration for the initial 1.8m - I wrote down 3ms^-2, but it's 2.5. You're right about 2.19s.
No wait I thought I made a mistake
17. (Original post by h26)
No wait I thought I made a mistake
Huh, I've no clue where they got that alternative a.

https://imgur.com/JmvXiN0
18. (Original post by plklupu)
Huh, I've no clue where they got that alternative a.

https://imgur.com/JmvXiN0
Lol me too! I worked it out in the end. But I solved 4.9T^2 -3T -1.8=0 to t=0.985 and then did v=u+at like you did to get 1.2 seconds. Added them together to get 2.19 seconds
Thanks for the pic of your working out
19. (Original post by h26)
No wait I thought I made a mistake
Page 54 is where C is.
20. (Original post by h26)
Lol me too! I worked it out in the end. But I solved 4.9T^2 -3T -1.8=0 to t=0.985 and then did v=u+at like you did to get 1.2 seconds. Added them together to get 2.19 seconds
Thanks for the pic of your working out
No probs! Happy to help

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