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    So I’ve got a question and I’ve been given one side, the angle and the area of an irregular triangle. How do I rearrange 1/2absin(c) to find a missing side. I’ve looked online and I don’t know if I’ve been searching the wrong things but I can’t find it and would appreciate if anyone could help.
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    (Original post by Shaijohnson)
    So I’ve got a question and I’ve been given one side, the angle and the area of an irregular triangle. How do I rearrange 1/2absin(c) to find a missing side. I’ve looked online and I don’t know if I’ve been searching the wrong things but I can’t find it and would appreciate if anyone could help.
    If you have A, a and C and

    A=\frac{1}{2}ab \sin C

    then the missing side b is calculated by rearranging the formula such that b is the subject of the formula, that is,

    b=\dfrac{2A}{a \sin C} .
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    Do you have a picture of the question?
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    (Original post by Shaijohnson)
    So I’ve got a question and I’ve been given one side, the angle and the area of an irregular triangle. How do I rearrange 1/2absin(c) to find a missing side. I’ve looked online and I don’t know if I’ve been searching the wrong things but I can’t find it and would appreciate if anyone could help.
    Name:  0523B5AB-CC58-4C61-BF9C-CEE741E51070.jpg.jpeg
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    (Original post by Shaijohnson)
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    Use Area=1/2xb sinC

    and rearrange to find x
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    Thank you
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    (Uploaded in two parts for some reason?) The question I’m asking is how to rearrange to find a missing side
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    Ok so we know:
    1/2xbSinC=36.7
    Multiply through by 2 to eliminate the 1/2
    Which gives us xbSinC=73.4
    Put in our values so x*13.8*Sin(45)=73.4
    Divide both sides by 13.8 to get
    Spoiler:
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    367/69

    Now divide both sides by sin(45) to get x on its own
    Spoiler:
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    x=7.5(1.d.p)
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