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# Converting Cartesian to Polar watch

1. How would you convert y = (2x+1) ^1/2 into polar. I used y^2 = r^2-x^2 and subbed that in.

It then gave me a quadratic which was (x+1)^2. So r^2= (x+1) ^2 .

Square root both side and I got r=x+1. so r = rcos theta + 1. Which isn't the answer. Can someone please help?

Thanks,
2. (Original post by ChemBoy1)
How would you convert y = (2x+1) ^1/2 into polar. I used y^2 = r^2-x^2 and subbed that in.

It then gave me a quadratic which was (x+1)^2. So r^2= (x+1) ^2 .

Square root both side and I got r=x+1. so r = rcos theta + 1. Which isn't the answer. Can someone please help?

Thanks,
There are potentially several different forms for the answer.

You want to express r as a function of theta - currently it's in implicit form - to start.
3. (Original post by ChemBoy1)
How would you convert y = (2x+1) ^1/2 into polar. I used y^2 = r^2-x^2 and subbed that in.

It then gave me a quadratic which was (x+1)^2. So r^2= (x+1) ^2 .

Square root both side and I got r=x+1. so r = rcos theta + 1. Which isn't the answer. Can someone please help?

Thanks,
You are not far from the answer. Try taking r = [email protected] + 1 are rearranging to make r the subject.

Edit: overlapped with ghostwalker

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Updated: February 18, 2018
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