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# Stats question watch

1. Hi some help with this question will be appreciated. I have only started learning about covariance and variance and standard deviation lately, so I am not sure how to solve this. For part a , the solution suggests something about 68%, but I am not sure what that is. Thanks
2. (Original post by coconut64)

Hi some help with this question will be appreciated. I have only started learning about covariance and variance and standard deviation lately, so I am not sure how to solve this. For part a , the solution suggests something about 68%, but I am not sure what that is. Thanks
The standard deviation is sqrt(625) = 25.

So for a), 425 is one standard deviation below the mean. In your notes/textbook you should have information about what percentage of data is within 1/2/3 standard deviations of the mean.

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