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1. The displacement, x m, of a particle from a fixed point O at time t s is given by
x= t^4 -4(t)^3-8(t)^2+1
Find the total distance travelled by the particle during the first 5 seconds of motion???
2. (Original post by jasperkearns)
The displacement, x m, of a particle from a fixed point O at time t s is given by
x= t^4 -4(t)^3-8(t)^2+1
Find the total distance travelled by the particle during the first 5 seconds of motion???
Total distance travelled is the total area between the velocity graph and the time axis, when plotted against velocity-time axes.
3. (Original post by RDKGames)
Total distance travelled is the total area between the displacement graph and the time axis, when plotted against time-displacement axes.
Ok thank you very much, so just integrate then?
4. (Original post by jasperkearns)
Ok thank you very much, so just integrate then?
OK, ignore that, I meant to say that you're looking for the total area between graph and the time axis on a velocity-time graph.

So, you need to consider (which you don't need to evaluate), but note that is -ve between t=0 and t=4 and positive between t=4 and t=5 therefore you need to make your area between t=0 and t=4 +ve before adding it onto the area from t=4 to t=5

So, the total distance traveled is just
5. (Original post by RDKGames)
Total distance travelled is the total area between the displacement graph and the time axis, when plotted against time-displacement axes.
That would be true for a velocity time graph.
6. (Original post by BuryMathsTutor)
That would be true for a velocity time graph.
...

Long day, I suppose
7. (Original post by RDKGames)
...

Long day, I suppose
I was struggling to believe that you had made a mistake, but we all do I suppose.

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