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1. So i have this question X satisfies the equation x^2=3x-1
I then showed that x+x^-1 =3
then i expanded (x+x^-1)^2
and then i expanded (x+x^-1)^3
Then the question says hence find the values of x^2 +x^-2 and x^3+x^-3
What do i do?
2. When you got to X+x-¹=3, multiply by x, then take away 3x, so you'll have x²-3x+1=0

Factorise that then find two X values that will equal 0. You might have to use the quadratic equation to find X, I haven't worked it out. When you have two values of X, sub each into the final equations as you stated.

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