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# integration watch

1. im unsure how to tackle this question

the diaggram show ths curve y=x^2-2x+3
and the sraight line y=x+7
which intersects at the points p and q
a) by solving a suitable quadratic, show that the x coordinate of p and q are -1 and 4
b) determine which of the regions a and b shaded on the diagram has the greater area
(image of question question in link)
https://imgur.com/a/RkAA9

can someone please explain how to do it

thankyou
2. Which part? Part a is simply solving an equation while part b you have to get values for both areas and then compare.
3. (Original post by Chez 01)
im unsure how to tackle this question

the diaggram show ths curve y=x^2-2x+3
and the sraight line y=x+7
which intersects at the points p and q
a) by solving a suitable quadratic, show that the x coordinate of p and q are -1 and 4
b) determine which of the regions a and b shaded on the diagram has the greater area
(image of question question in link)
https://imgur.com/a/RkAA9

can someone please explain how to do it

thankyou
For part a, since both y=x^2-2x+3 and y=x+7 then x^2-2x+3=x+7.
For part b, integrate the curve between the coordinates of P and Q this will give you the area of region A and then to calculate the area of region B you will have to calculate the area of the trapezium under the line PQ and then subtract the area of region A.

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