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# Maths question helpM 2 watch

1. Show that 268 can be written as the sum of a power of 3 and a square number
2. Plz help
3. 3^5 + 5^2
4. (Original post by Needhelp90)
Show that 268 can be written as the sum of a power of 3 and a square number
Anyone ???
5. No idea
6. So 268 = 3^x + n^2.

Use trial and error. We know 25 + 243 = 268 so 5^2 + 3^5
7. (Original post by thekidwhogames)
So 268 = 3^x + n^2.

Use trial and error. We know 25 + 243 = 268 so 5^2 + 3^5
Lol ur early
8. (Original post by Needhelp90)
Show that 268 can be written as the sum of a power of 3 and a square number
List all the powers of 3 under 268:

3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243

Take 243 away from 268:
268 - 243 = 25

25 is a square number because 5^2 = 25

So we can rewrite 268 as 3^5 + 25

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