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    Hi,

    Can someone help me out with this question. Find the integral of (Cosech x) (Coth x)

    I know the relationship where coth^2 = cosech^2+1. But when I sub it in it makes the integral look very complicated. Is there a simpler way?
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    (Original post by ChemBoy1)
    Hi,

    Can someone help me out with this question. Find the integral of (Cosech x) (Coth x)

    I know the relationship where coth^2 = cosech^2+1. But when I sub it in it makes the integral look very complicated. Is there a simpler way?
    Just express the thing you're intergrating in terms of sinh and cosh then use the obvious substitution for integration
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    Hi,
    Just did that so I got cosh/ sinh^2. Subbed in Sinh = 1+ cosh^2.
    So now I have cosh/ cosh^2 +1. Subbed in u= cosh, but this is where I get stuck:
    du/dx equals Sinh so dx= du/ sinh. I can't seem to find a way to get rid of the sinh?
    (Original post by RDKGames)
    Just express the thing you're intergrating in terms of sinh and cosh then use the obvious substitution for integration
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    (Original post by ChemBoy1)
    Hi,
    Just did that so I got cosh/ sinh^2. Subbed in Sinh = 1+ cosh^2.
    So now I have cosh/ cosh^2 +1. Subbed in u= cosh, but this is where I get stuck:
    du/dx equals Sinh so dx= du/ sinh. I can't seem to find a way to get rid of the sinh?
    Er.. no I just meant you go straight to u-sub with u=\sinh x after converting the expression.
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    So I got cosh x / sinh x ^2. If i sub in u = sinh x what would the numerator be?
    (Original post by RDKGames)
    Er.. no I just meant you go straight to u-sub with u=\sinh x after converting the expression.
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    (Original post by ChemBoy1)
    So I got cosh x / sinh x ^2. If i sub in u = sinh x what would the numerator be?
    Substitute in for dx
 
 
 
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