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    So i have the graph y=natural log of Kx
    I answered the first question but the second question I can't do

    I have the find the vurticle translati0n vector

    it's not x,ky is it?
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    (Original post by mariejuana)
    So i have the graph y=natural log of Kx
    I answered the first question but the second question I can't do

    I have the find the vurticle translati0n vector

    it's not x,ky is it?
    What?
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    (Original post by RDKGames)
    What?
    The graph of lnx can be transformed into the graph of y=lnkx by using a horizontal or verticle translation
    find verticle translation vector
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    (Original post by mariejuana)
    The graph of lnx can be transformed into the graph of y=lnkx by using a horizontal or verticle translation
    find verticle translation vector
    You cannot do it by horizontal translation.

    As for vertical, yes there is a translation vector. It is not "k,xy" or whatever it is you meant here.

    Consider the fact that \ln (kx) = \ln k + \ln x
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    [QUOTE=RDKGames;76251488]You cannot do it by horizontal translation.
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    (Original post by mariejuana)
    is this utter nonsense >?
    Yes.
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    (Original post by RDKGames)
    Yes.
    Can you tell me how to start. i have no idea what to do AT ALL
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