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# Circuits questions help!! watch

1. In the circuit, the batteries have negligible internal resistance and the voltmneter V has a very high resistance. What would be the reading of the voltmeter?Attachment 727152

Thank you!
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2. (Original post by gannaspanner)
In the circuit, the batteries have negligible internal resistance and the voltmneter V has a very high resistance. What would be the reading of the voltmeter?Attachment 727152

Thank you!
No attachment?
3. what do you mean?
the picture is right there
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5. (Original post by the bear)
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6. the total resistance in the circuit is 60 + {40R/(40 + R)} ohms, where R is the resistance of the voltmeter.

the voltage drop across the 60 ohm resistor must be 2.5 volts.

you can find the current flowing through the 60 ohm resistor... then find R
7. 8D(ii) i=(10- 8)/(40+10)=0,04A -> V voltometer = 8 + 0,04*40 = 9,6V
8. Sorry I meant this one
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9. i=(10- 8)/(40+10)=0,04A -> V voltometer = 8 + 0,04*40 = 9,6V

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