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# Circuits questions help!! watch

1. In the circuit, the batteries have negligible internal resistance and the voltmneter V has a very high resistance. What would be the reading of the voltmeter?Attachment 727152

Thank you!
2. (Original post by gannaspanner)
In the circuit, the batteries have negligible internal resistance and the voltmneter V has a very high resistance. What would be the reading of the voltmeter?Attachment 727152

Thank you!
No attachment?
3. what do you mean?
the picture is right there
5. (Original post by the bear)
6. the total resistance in the circuit is 60 + {40R/(40 + R)} ohms, where R is the resistance of the voltmeter.

the voltage drop across the 60 ohm resistor must be 2.5 volts.

you can find the current flowing through the 60 ohm resistor... then find R
7. 8D(ii) i=(10- 8)/(40+10)=0,04A -> V voltometer = 8 + 0,04*40 = 9,6V
8. Sorry I meant this one
9. i=(10- 8)/(40+10)=0,04A -> V voltometer = 8 + 0,04*40 = 9,6V

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